Quote:
Originally Posted by rank
Are you sure you're interpreting that requirement to restrict .4g movement in the forward direction properly? I've never been able to make any sense of it..... so I go with their WLL rules instead.
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Well, I spent half an hour searching online for the answer how this stupid 0.5 g and 0.43 g acceleration is connected to WLL of chains and wasn't able to find anything. This being a Sunday
but I had nothing else to do so I kept at it until I got the answer. This is your lucky day, rank
and I guess mine too. Here's what I found.
In the Canadian regulations they list pretty much the same G FORCE acceleration/deacceleration requirements which both you and I now know are impossible to interpret unless you have a Ph.D. in physics
So the smart Canadians follow that useless list of the minimum G forces with this little clause:
"Equivalent means of securement
Where cargo transported by a vehicle is contained, immobilized or secured in accordance with the applicable requirements of Divisions 3, 4 and 5 and Part 2, it meets the requirements of Section 5."
Now, Section 5 was the one with the G requirements and then I looked up Divisions 3,4 and 5 and guess what? That's where they list the familiar AGGREGATE WORKING LOAD LIMIT REQUIREMENT! The one that says you must use enough WLLs to cover 50% of the weight of the cargo.
So, I return to the US Federal Regulations and right below the G force stupid clause, there's this:
EQUIVALENT MEANS OF SECUREMENT 393.102 C
THE MEANS OF SECURING ARTICLES OF CARGO ARE CONSIDERED TO MEET THE PERFORMANCE REQUIREMENTS OF THIS SECTION IF THE CARGO IS:
1.
2.
3. SECURED IN ACCORDANCE WITH THE APPLICABLE REQUIREMENTS OF ##393.104 THROUGH 393.136!!!!
So, since very few cops and dot officers have ph.d. in physics, as long as the AGGREGATE WORKING LOAD LIMIT FOR TIEDOWNS (#393.106 D) is met, the g force requirement is deemed to have been met.
Which means you rank has been doing it correctly all along. G force bad, WLL good