Turbo 3000, absolute garbage!
#21
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Location: Southern Maryland
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Originally Posted by heavyhaulerss
The reason the fuel ignites is due to the ideal gas law (and since no elements of Avogadro's law will apply, it's a little easier to look at the combined gas law:
pV=nRT p=pressure V=volume n is amount of a chemical R is a constant T=temperature. In a four stroke engine, just look at TDC and BDC. n and R drop out. Going from BDC (let's say fuel and air go in here) to TDC: p goes up, V goes down. p goes up more than V goes down, T has to rise to compensate. At some point, T is high enough for fuel to burn. Pistons move. Truck moves. We get paid. (well, you, since I'm not driving yet) what language is this ???? :? :lol: ![]() To put it in English: When you squeeze a gas, it shrinks and/or it gets warmer. Squeeze it enough, and it will combust. Like diesel in an engine.
#22
Originally Posted by gmh
Originally Posted by heavyhaulerss
The reason the fuel ignites is due to the ideal gas law (and since no elements of Avogadro's law will apply, it's a little easier to look at the combined gas law:
pV=nRT p=pressure V=volume n is amount of a chemical R is a constant T=temperature. In a four stroke engine, just look at TDC and BDC. n and R drop out. Going from BDC (let's say fuel and air go in here) to TDC: p goes up, V goes down. p goes up more than V goes down, T has to rise to compensate. At some point, T is high enough for fuel to burn. Pistons move. Truck moves. We get paid. (well, you, since I'm not driving yet) what language is this ???? :? :lol: ![]() To put it in English: When you squeeze a gas, it shrinks and/or it gets warmer. Squeeze it enough, and it will combust. Like diesel in an engine. Maybe what you meant to say is ; "squeeze it enough, and it will heat up the air charge enough to cause an 'introduced flammable' to combust".
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Bob H
#24
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Originally Posted by bob h
Originally Posted by gmh
Originally Posted by heavyhaulerss
The reason the fuel ignites is due to the ideal gas law (and since no elements of Avogadro's law will apply, it's a little easier to look at the combined gas law:
pV=nRT p=pressure V=volume n is amount of a chemical R is a constant T=temperature. In a four stroke engine, just look at TDC and BDC. n and R drop out. Going from BDC (let's say fuel and air go in here) to TDC: p goes up, V goes down. p goes up more than V goes down, T has to rise to compensate. At some point, T is high enough for fuel to burn. Pistons move. Truck moves. We get paid. (well, you, since I'm not driving yet) what language is this ???? :? :lol: ![]() To put it in English: When you squeeze a gas, it shrinks and/or it gets warmer. Squeeze it enough, and it will combust. Like diesel in an engine. Maybe what you meant to say is ; "squeeze it enough, and it will heat up the air charge enough to cause an 'introduced flammable' to combust". But I'm also not sure if that matters much
#25
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Location: jackassville (winnipeg, mb)
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In a gas engine they are.
In a diesel like ours, the air is compressed about 18:1. Then the diesel is injected, and ignites as soon as it's injected. There is no "mixture" in the common sense.
#26
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Originally Posted by allan5oh
In a gas engine they are.
In a diesel like ours, the air is compressed about 18:1. Then the diesel is injected, and ignites as soon as it's injected. There is no "mixture" in the common sense. Thanks.
#27
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Join Date: Nov 2007
Posts: 1,513
Originally Posted by gmh
Originally Posted by bob h
Originally Posted by gmh
Originally Posted by heavyhaulerss
The reason the fuel ignites is due to the ideal gas law (and since no elements of Avogadro's law will apply, it's a little easier to look at the combined gas law:
pV=nRT p=pressure V=volume n is amount of a chemical R is a constant T=temperature. In a four stroke engine, just look at TDC and BDC. n and R drop out. Going from BDC (let's say fuel and air go in here) to TDC: p goes up, V goes down. p goes up more than V goes down, T has to rise to compensate. At some point, T is high enough for fuel to burn. Pistons move. Truck moves. We get paid. (well, you, since I'm not driving yet) what language is this ???? :? :lol: ![]() To put it in English: When you squeeze a gas, it shrinks and/or it gets warmer. Squeeze it enough, and it will combust. Like diesel in an engine. Maybe what you meant to say is ; "squeeze it enough, and it will heat up the air charge enough to cause an 'introduced flammable' to combust". But I'm also not sure if that matters much ![]() yeah; there's a big difference....what you & I are thinking in terms of is what's know as the OTTO Cycle---the way a gasoline or jet fuel works......where the air/fuel is combined first then ignited with a spark--- the diesel combustion system seams very simple---- allowing just about anything that will burn to be used from peanut oil to diesel. I too would be interested in how/when exactly the fuel is injected in relationship to piston position, how the fire/explosion is prevented from traveling back into the fuel rail, and how much remaining chamber space is remaining when the pistons are at TDC? Assuming the fuel is injected exactly when the piston is TDC? otherwise, it too would be getting "compressed' during the compression stroke(along with the chamber air), which would seem to problematic---resulting in severe timing problems.
#28
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http://auto.howstuffworks.com/diesel.htm
http://en.wikipedia.org/wiki/Diesel_engine The fuel injector pressure is rather substantial, even in older engines. I'm sure the injector is closed by the time max pressure has occured.
#29
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Originally Posted by allan5oh
http://auto.howstuffworks.com/diesel.htm
http://en.wikipedia.org/wiki/Diesel_engine The fuel injector pressure is rather substantial, even in older engines. I'm sure the injector is closed by the time max pressure has occured.
#30
Originally Posted by allan5oh
http://auto.howstuffworks.com/diesel.htm
http://en.wikipedia.org/wiki/Diesel_engine The fuel injector pressure is rather substantial, even in older engines. I'm sure the injector is closed by the time max pressure has occured. Maximum combustion chamber pressure is far lower than the fuel injector's "valve opening pressure".
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