Where am I ???
#5
Originally Posted by roadhog
Somewhere near Moab, Utah? and Arches National Park?
I just got real bored, and did a photo search of Moab, and found the same arch. Actually only took 5 minutes... so I'm bored again. :?
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#6
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Originally Posted by roadhog
Originally Posted by roadhog
Somewhere near Moab, Utah? and Arches National Park?
I just got real bored, and did a photo search of Moab, and found the same arch. Actually only took 5 minutes... so I'm bored again. :? ![]()
#7
That was easy.
I identified the arch as "Wilson Arch." It is on Hwy 191 (91-parent road) 24 miles south of Moab, Utah. You had to park on the pull-off on the eastern side of the Arch and walk back to make the photo you took. I triangulated the position in which you were standing for the photo, taking in account declination factors, rotational angle using the date you gave, wind speed and temperature for that mid-day, and measured shadow effect for precise positioning, and I came up with these coordinates; 38 degrees 16' 22.45" N 109 degrees 22.24' 12" W It took me 7 minutes, but I left my computer to get a cup of coffee, but I did most of the math in my head, lost count when I spooned in creamer and had to start over. wotta did I win? :?
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#8
Originally Posted by roadhog
That was easy.
I identified the arch as "Wilson Arch." It is on Hwy 191 (91-parent road) 24 miles south of Moab, Utah. You had to park on the pull-off on the eastern side of the Arch and walk back to make the photo you took. I triangulated the position in which you were standing for the photo, taking in account declination factors, rotational angle using the date you gave, wind speed and temperature for that mid-day, and measured shadow effect for precise positioning, and I came up with these coordinates; 38 degrees 16' 22.45" N 109 degrees 22.24' 12" W It took me 7 minutes, but I left my computer to get a cup of coffee, but I did most of the math in my head, lost count when I spooned in creamer and had to start over. wotta did I win? :? That's some intense research. :lol:
#9
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Originally Posted by roadhog
That was easy.
I identified the arch as "Wilson Arch." It is on Hwy 191 (91-parent road) 24 miles south of Moab, Utah. You had to park on the pull-off on the eastern side of the Arch and walk back to make the photo you took. I triangulated the position in which you were standing for the photo, taking in account declination factors, rotational angle using the date you gave, wind speed and temperature for that mid-day, and measured shadow effect for precise positioning, and I came up with these coordinates; 38 degrees 16' 22.45" N 109 degrees 22.24' 12" W It took me 7 minutes, but I left my computer to get a cup of coffee, but I did most of the math in my head, lost count when I spooned in creamer and had to start over. wotta did I win? :?:lol: :lol: :lol: :lol: :lol: You win an expired shower coupon from the Hook!!!! |
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