I need some help with something I've been kicking around a little. I have an '01 FL Columbia sitting in my driveway, but for now, I'm still driving for Maverick flatbed. My truck is actually a 24' straight truck (expediter).
I've been kicking around the idea of adding some lift axles and a flatbed to it and build a 24' flatbed straight truck. I would want to get as close to an 80,000 GVWR as possible.
My question:
If I add lift axles to the point that I have 4 rear axles (5 total counting the steer), how much weight could I legally gross? I would have approximately a 370" wheelbase from the front axle to the rear axle and 220" between the steer axle and the 1st rear lift axle. This is assuming a 50" spacing between the centerline of each of the rear axles (I think this is fairly accurate).
I would defintely make the two lift axles in front of the drive steerable. I would also have the option of adding some more space between the drive axle and the 2 steerable lift axles. How much space would be required to gain any GVWR?
The bridge laws are fairly confusing to me. Can anyone explain it?
I don't think i would gain anything with this set-up over a traditional t/t flatbed. The straight truck would be a breeze to get around in though. I know that a large percentage of the loads I pull at Maverick would fit on a 24' bed, but I'm not sure if I can get the GVWR up high enough to have a decent payload.
Thanks for help on the bridge laws.
Arky




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